Atomic Structure Question 306
Question: If the wavelength of the electromagnetic radiation is increased to thrice the digital value, then what will be the percent change in the value of frequency of the electromagnetic radiation.
Options:
A) Increases by 33%
B) Decreases by 33%
C) Increases by 66%
D) Decreases by 66%
Show Answer
Answer:
Correct Answer: D
Solution:
- $ v_1=\frac{c}{{\lambda_1}} $
$ v_2=\frac{c}{{\lambda_2}}=\frac{c}{3{\lambda_1}} $ % change in frequency $ =\frac{v_2-V_1}{v_1}\times 100 $
$ =\frac{\frac{c}{3{\lambda_1}}-\frac{c}{{\lambda_1}}}{\frac{c}{{\lambda_1}}}\times 100=\frac{-\frac{2c}{3{\lambda_1}}\times 100}{\frac{c}{{\lambda_1}}} $
$ =-66% $ %
BETA
