Atomic Structure Question 337
Question: Time taken for an electron to complete one revolution in the Bohr orbit of hydrogen atom is [Kerala PMT 2004]
Options:
A) $ \frac{4{{\pi }^{2}}mr^{2}}{nh} $
B) $ \frac{nh}{4{{\pi }^{2}}mr} $
C) $ \frac{nh}{4{{\pi }^{2}}mr^{2}} $
D) $ \frac{h}{2\pi mr} $
Show Answer
Answer:
Correct Answer: A
Solution:
It will take $ \frac{4{{\pi }^{2}}mr^{2}}{n,h} $
BETA
