Atomic Structure Question 353
Question: Magnetic moments of $ Cr(Z=24),,Mn(Z=25) $ and $ Fe(Z=26) $ are $ x,,y $ and $ z $ respectively.
Hence,
Options:
A) $ x=y=z $
B) $ x=y<z $
C) $ x<y<z $
D) $ x>y>z $
Show Answer
Answer:
Correct Answer: D
Solution:
- $ Cr(24)=1s^{2},,2s^{2},,2p^{6},,3s^{2},,3p^{6},,4s^{1},,3d^{5} $ $ Mn,(25)=1s^{2},,2s^{2},,2p^{6},,3p^{6},,4s^{2},,3d^{5} $ $ Fe(26)=1s^{2},,2s^{2},,2p^{6},,3s^{2},,3p^{6},,4s^{2},,3d^{6} $ Magnetic moment $ (\mu )=\sqrt{n(n+2)} $ where, $ n= $ number of unpaired electrons. Greater the number of unpaired electrons, greater will be the magnetic moment.
BETA
