Atomic Structure Question 360
The wave number of first line of Balmer series of hydrogen is $ 15200,cm^{-1} $ . The wave number of first Balmer line of $ Li^{2+} $ ion is
Options:
A) $ 15200,c{m^{-1}} $
B) $ 60800,c{m^{-1}} $
C) $ 76000,c{m^{-1}} $
D) $ 136800,c{m^{-1}} $
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Answer:
Correct Answer: D
Solution:
- v for hydrogen like species $ =v_{H}\times Z^{2}=15200\times 3^{2}=15200\times 9=136800,c{m^{-1}} $
BETA
