Atomic Structure Question 381
Question: The following transition occurs when Lithium atoms are sprayed into hot flame. The various steps are numbered for identification.
$ 2s\xrightarrow{I}2p\xrightarrow{II}3d\xrightarrow{III}3p\xrightarrow{IV} $
$ 4s\xrightarrow{V}3p $ Which of these transitions result in emission of light?
Options:
A) I, II, and V
B) III & V
C) III, IV, and V
All
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Answer:
Correct Answer: B
Solution:
- $ 2s\xrightarrow{I}2p\xrightarrow{II}3d\xrightarrow{III}3p\xrightarrow{IV}4s\xrightarrow{V}3p $ Energy of 3d is higher than 3p therefore it will emit energy, similarly from $ 4s\to 3p $ transition.
BETA
