Atomic Structure Question 487
Question: The de-Broglie wavelength of a particle with mass $ 1gm $ and velocity $ 100m/\sec $ is [CBSE PMT 1999; EAMCET 1997; AFMC 1999; AIIMS 2000]
Options:
A) $ 6.63\times {10^{-33}}m $
B) $ 6.63\times {10^{-34}}m $
C) $ 6.63\times {10^{-35}}m $
D) $ 6.65\times {10^{-35}}m $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \lambda =\frac{h}{mv}=\frac{6.63\times {10^{-34}}}{{10^{-3}}\times 100}=6.63\times {10^{-33}}m $
BETA
