Atomic Structure Question 495
Question: If the velocity of hydrogen molecule is $ 5\times 10^{4}cm,se{c^{-1}} $ , then its de-Broglie wavelength is
Options:
A) $ 2{\AA} $
B) $ 4{\AA} $
C) $ 8{\AA}~ $
D) $ 100{\AA} $
Show Answer
Answer:
Correct Answer: B
Solution:
According to de-Broglie $ \lambda =\frac{h}{mv}=\frac{6.62\times {10^{-20}}erg.,\sec }{\frac{2}{6.023\times 10^{23}}\times 5\times 10^{4}cm/\sec } $
$ =\frac{6.62\times {10^{-27}}\times 6.023\times 10^{23}}{2\times 5\times 10^{4}}cm $
$ =4\times {10^{-8}}cm=4 \AA $ .
BETA
