Atomic Structure Question 510
Question: In Bohr series of lines of hydrogen spectrum, third line from the red end corresponds to which one of the following inner orbit jumps of electron for Bohr’s orbit in atom of hydrogen
Options:
A) 4 $ \to $ 1
B) 2 $ \to $ 5
C) 3 $ \to $ 2
D) 5 $ \to $ 2
Show Answer
Answer:
Correct Answer: D
Solution:
- The emission is in visible (VIBGYOR) region. Thus, Balmer series is, that is, either [c] or [d]. in [c] there is only one emission, the third line will be in the jump from 5 to 2.
BETA
