Biomolecules Question 131
Question: Identity X, Y and Z from the information given below: X = A chiral amino acid which loses its chirality on treatment with lithium aluminum hydride. Y= the decarboxylation product of a-amino (secondary) acid, $ C_5H_9O_2N $ . Z = It is formed when A ( $ C_3H_4O_3 $ ) is treated with (i) $ NH_3 $ (ii) $ NaBH_4 $ [A forms oxime, gives iodoform test and liberate $ CO_2 $ with $ NaHCO_3 $ ].
Options:
A)
| X | YZ |
|---|---|
| Alanine | Serine |
B)
| X | YZ |
|---|---|
| Serine | Alanine |
C)
| X | YZ |
|---|---|
| Serine | Alanine |
D)
| X | YZ |
|---|---|
| Aspartic acid | Serine |
Show Answer
Answer:
Correct Answer: C
Solution:
[c] 
BETA
