Biomolecules Question 205
Question: The enantiomer of $ \alpha -D-( + ) $ -glucose is
Options:
A) $ \beta -D-( + ) $ -glucose
B) $ \alpha -D-( - ) $ -glucose
C) $ \alpha -L-( - ) $ -glucose
D) $ \beta -L-( - ) $ -glucose.
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Answer:
Correct Answer: C
Solution:
[c] In the D family the more dextrorotatory anomer is named $ \alpha $ -D-. In the L family the more laevorotatory anomer is named $ \alpha $ L. so it is $ \alpha -L-( - ) $ -glucose
BETA
