Biomolecules Question 7
Question: The dipeptide, Gly. Ala has structure -
Options:
A) $ H_3\overset{+}{\mathop{N}}CH_2\overset{O}{\mathop{\overset{||}{\mathop{C}}}}NH\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}HC{{\bar{O}}_2} $
B) $ H_3\overset{+}{\mathop{N}}\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H\overset{O}{\mathop{\overset{||}{\mathop{C}}}}NH\underset{{}}{\mathop{\underset{{}}{\mathop{C}}}}H_2C{{\overset{-}{\mathop{O}}}_2} $
C) $ {{\overset{-}{\mathop{O}}}_2}C\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}HNH-\overset{O}{\mathop{\overset{||}{\mathop{C}}}}-\underset{{}}{\mathop{\underset{{}}{\mathop{C}}}}H_2\overset{+}{\mathop{N}}H_3 $
D) $ {{\overset{-}{\mathop{O}}}_2}CCH_2NH-\overset{O}{\mathop{\overset{||}{\mathop{C}}}}\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}H\overset{+}{\mathop{N}}H_3 $
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Answer:
Correct Answer: A
Solution:
[a] By convention, the amino acid with the free amino group (N-terminal) is written at the left end and the one with the unreacted carboxyl group (C-terminal) at the right end. Thus, the structure of Gly. Ala is $ H_3\overset{+}{\mathop{N}}CH_2\overset{O}{\mathop{\overset{||}{\mathop{C}}}}NH\underset{CH_3}{\mathop{\underset{|}{\mathop{C}}}}HC{{\overset{-}{\mathop{O}}}_2} $
BETA
