Carboxylic Acids Question 115
Question: $ RCOOH $ on treatment with $ PCl_5 $ and $ KCN, $ is subjected to hydrolysis followed by Clemmensen’s reduction, the product obtained is
[Kerala PMT 2004]
Options:
A) $ RCH_2-COCl $
B) $ RCH_2-COOH $
C) $ RCOCN $
D) $ RCN $
E) $ R-OH $
Show Answer
Answer:
Correct Answer: B
Solution:
$ RCOOH+PCl_5\to RCOCl+POCl_3+HCl\xrightarrow{KCN} $
$ RCOCN+KCl\xrightarrow{2H_2O}RCOCOOH+2NH_3 $
$ \underset{Zn-Hg/Conc.\ HCl}{\mathop{\xrightarrow{Clemenson\ reduction}}}RCH_2COOH+H_2O $
BETA
