Carboxylic Acids Question 17
Question: The product D of the reaction $ CH_3Cl\xrightarrow{KCN}(A)\xrightarrow{H_2O}(B)\xrightarrow{NH_3}(C)\xrightarrow{\Delta }(D) $ is
[MP PET 1997]
Options:
A) $ CH_3CH_2NH_2 $
B) $ CH_3CN $
C) $ HCONH_2 $
D) $ CH_3CONH_2 $
Show Answer
Answer:
Correct Answer: D
Solution:
$ CH_3Cl\underset{-KCl}{\mathop{\xrightarrow{KCN}}}CH_3CN\xrightarrow{H_2O}CH_3COOH $
$ \xrightarrow{NH_3}CH_3COONH_4\xrightarrow{\Delta }CH_3CONH_2 $
BETA
