Carboxylic Acids Question 21
Question: Two moles of acetic acid are heated with $ P_2O_5. $ The product formed is
[MP PET/PMT 1988]
Options:
A) 2 moles of ethyl alcohol
B) Formic anhydride
C) Acetic anhydride
D) 2 moles of methyl cyanide
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Answer:
Correct Answer: C
Solution:
$ \begin{matrix} CH_3COOH \\ CH_3COOH \\ \end{matrix}+P_2O_5\to \begin{matrix} CH_3-CO \\ CH_3-CO \\ \end{matrix}>O+H_2O $
BETA
