Carboxylic Acids Question 4
Question: When $ CH_2=CH-COOH $ is reduced with $ LiAlH_4 $ , the compound obtained will be
[AIEEE 2003]
Options:
A) $ CH_3-CH_2-COOH $
B) $ CH_2=CH-CH_2OH $
C) $ CH_3-CH_2-CH_2OH $
D) $ CH_3-CH_2-CHO $
Show Answer
Answer:
Correct Answer: B
Solution:
$ CH_2=CH-COOH\xrightarrow{LiAlH_4} $
$ CH_2=CH-CH_2OH+H_2O $
BETA
