Carboxylic Acids Question 40
Question: $ R-CH_2-CH_2OH $ can be converted into $ RCH_2CH_2COOH. $ The correct sequence of the reagents is
[AIIMS 1997]
Options:
A) $ PBr_3,KCN,H_3{O^{+}} $
B) $ PBr_3,KCN,H_2 $
C) $ HCN,PBr_3,{H^{+}} $
D) $ KCN,{H^{+}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ R-CH_2CH_2OH\xrightarrow{PBr_3}R-CH_2CH_2-Br $
$ \xrightarrow{KCN}R-CH_2-CH_2-CN\xrightarrow{H_3{O^{+}}} $
$ R-CH_2-CH_2COOH+NH_3 $
BETA
