Carboxylic Acids Question 47
Question: $ CH_3CONH_2\xrightarrow{NaNO_2/HCl}X $
[Pb. CET 2003]
Options:
A) $ CH_3COOH $
B) $ CH_3CO\overset{+}{\mathop{N}}H_3C{l^{-}} $
C) $ CH_3NH_2 $
D) $ CH_3CHO $
Show Answer
Answer:
Correct Answer: A
Solution:
Amide, on treating with $ HNO_2, $ give acids. $ CH_3CONH_2\underset{(HNO_2)}{\mathop{\xrightarrow{NaNO_2/HCl}}}\underset{aceticacid}{\mathop{CH_3COOH}}+N_2+H_2O $
BETA
