Carboxylic Acids Question 98
Acetyl chloride is reduced with $ LiAlH_4 $, the product formed is
[SCRA 1990]
Options:
A) Methyl alcohol
B) Ethyl alcohol
C) Acetaldehyde
D) Acetone (CHβ)βCO
Show Answer
Answer:
Correct Answer: B
Solution:
$ CH_3COCl\xrightarrow{LiAlH_4}CH_3CH_2OH+HCl $
 BETA
  BETA 
             
             
           
           
           
          