Carboxylic Acids Question 98

Acetyl chloride is reduced with $ LiAlH_4 $, the product formed is

[SCRA 1990]

Options:

A) Methyl alcohol

B) Ethyl alcohol

C) Acetaldehyde

D) Acetone (CH₃)β‚‚CO

Show Answer

Answer:

Correct Answer: B

Solution:

$ CH_3COCl\xrightarrow{LiAlH_4}CH_3CH_2OH+HCl $



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