Chemical Bonding And Molecular Structure Question 16
Question: The electronic configuration of four elements are given in brackets $ L,( 1s^{2},2s^{2}2p^{1} );M,( 1s^{2},2s^{2},2p^{5} ) $
$ Q,( 1s^{2},2s^{2},2p^{6},3s^{1} );R,( 1s^{2},2s^{2},2p^{2} ) $ The element that would most readily form a diatomic molecule is [NCERT 1983]
Options:
A) Q
B) M
C) R
D) L
Show Answer
Answer:
Correct Answer: B
Solution:
Non-metals readily form diatomic molecules by sharing of electrons. Element $ M,(1s^{2},2s^{2},2p^{5}) $ has seven electrons in its valence shell and thus needs one more electron to complete its octet. Therefore, two atoms share one electron each to form a diatomic molecule $ (M_2) $
$ :\underset{..}{\mathop{\overset{..}{\mathop{M}},}},.+.\overset{..}{\mathop{\underset{..}{\mathop{M}},}},: $
$ \to $
$ :\underset{..}{\mathop{\overset{..}{\mathop{M}},}},:\overset{..}{\mathop{\underset{..}{\mathop{M}},}},: $
BETA
