Chemical Bonding And Molecular Structure Question 293
Question: The dipole moments of diatomic molecules AB and CD are 10.41D and 10.27 D, respectively while their bond distances are 2.82 and $ 2.67\overset{o}{\mathop{A}}, $ , respectively. This indicates that
Options:
A) bonding is 100% ionic in both the compounds
B) AB has more ionic bond character than CD
C) AB has less ionic bond character than CD
D) bonding is nearly covalent in both molecules
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Answer:
Correct Answer: C
Solution:
As dipole moment = electric charge $ \times $ bond length $ \times $ cosine of the bond angle
D. M. of AB molecule $ =4.8\times {10^{-10}}\times 2.82\times {10^{-8}}=1.353\times {10^{-15}}D $
D.M. of CD molecule $ =4.8\times {10^{-10}}\times 2.67\times {10^{-8}}=1.281\times {10^{-15}}D $
Now % ionic character $ =\frac{Actual\ dipole\ moment\ of\ the\ bond}{Dipole\ moment\ of\ pure\ ionic\ compound}\times 100 $ then % ionic character in AB
$ =\frac{10.41}{13.53}\times 100=76.94 $ %
% ionic character in C-D $ =\frac{10.27}{12.81}\times 100=80.17 $ %
BETA
