Chemical Bonding And Molecular Structure Question 369
Question: Correct order of bond energy is
Options:
A) $ N_2>N_2^{+}>N_2^{-}>N_2^{2-} $
B) $ N_2^{+}>N_2^{-}>N_2^{2-}>N_2 $
C) $ N_2>N_2^{+}=N_2^{-}>N_2^{2-} $
D) $ N_2^{-}>N_2^{{}}=N_2^{+}>N_2^{2-} $
Show Answer
Answer:
Correct Answer: C
Solution:
- Bond order of various species $ N_2=3;N_2^{+}=2.5;N_2^{-}=2.5; $
$ N_2^{2-}=2; $ Bond order $ \propto $ bond energy. Hence, order is $ N_2>N_2^{+}=N_2^{-}>N_2^{2-} $
BETA
