Chemical Bonding And Molecular Structure Question 44
Question: As the s-character of hybridisation orbital increases, the bond angle
Options:
A) Increases
B) Decreases
C) Becomes zero
D) Does not change
Show Answer
Answer:
Correct Answer: A
Solution:
s-character increases with increase in bond angle. Hybridization s% Angle Sp 50 $ 180^{o} $
$ sp^{2} $ 33.3 $ 120^{o} $
$ sp^{3} $ 25 $ {{109.28}^{o}} $
$ sp^{3}d^{1} $ 20 $ 90^{o} $ and $ 120^{o} $
BETA
