Chemical Bonding And Molecular Structure Question 491
Question: The dipole moment of HBr is $ 1.6\times {10^{-30}} $ cm and interatomic spacing is 1Å. The % ionic character of HBr is
Options:
A) 7
B) 10
C) 15
D) 27
Show Answer
Answer:
Correct Answer: B
Solution:
Charge of $ {e^{-}}=1.6\times {10^{-19}} $ Dipole moment of $ HBr=1.6\times {10^{-30}} $ Inter atomic spacing $ =1\AA=1\times {10^{-10}}m $ % of ionic character in $ HBr=\frac{dipole,moment,of,HBr\times 100}{inter,spacing,distance,\times q} $
$ =\frac{1.6\times {10^{-30}}}{1.6\times {10^{-19}}\times {10^{-10}}}\times 100 $
$ ={10^{-30}}\times 10^{29}\times 100={10^{-1}}\times 100 $
$ =0.1\times 100=10% $
BETA
