Chemical Kinetics Question 102
Question: For the reaction $ H_2(g)+I_2(g) $ ⇌ $ 2HI(g) $ , the rate of reaction is expressed as [CBSE PMT 1997; AIEEE 2002]
Options:
A) $ -\frac{\Delta [I_2]}{\Delta t}=-\frac{\Delta [H_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [HI]}{\Delta t} $
B) $ \frac{\Delta [I_2]}{\Delta t}=\frac{\Delta [H_2]}{\Delta t}=\frac{\Delta [HI]}{2\Delta t} $
C) $ \frac{\Delta [H_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [I_2]}{\Delta t}=-\frac{\Delta [HI]}{\Delta t} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
For the given reaction :
$ -\frac{\Delta [I_2]}{\Delta t}=-\frac{\Delta [H_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [HI]}{\Delta t} $
BETA
