Chemical Kinetics Question 136
Question: In the reaction, $ A+2B\xrightarrow{{}}6C+2D $ , If the initial rate $ -\frac{d[A]}{dt} $ at t = 0 is $ 2.6\times {10^{-2}}Mse{c^{-1}} $ what will be the value of $ \frac{d[B]}{dt} $ at $ t=0 $ -
Options:
A) $ 8.5\times {10^{-2}}Mse{c^{-1}} $
B) $ 2.5\times {10^{-2}}Mse{c^{-1}} $
C) $ 5.2\times {10^{-2}}Mse{c^{-1}} $
D) $ 7.5\times {10^{-2}}Mse{c^{-1}} $
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Answer:
Correct Answer: C
Solution:
[c] Rate of reaction $ =\frac{Rateofdisappearance/appearance}{Stoichiometriccoefficient} $
$ =-\frac{d[A]}{dt}=\frac{1}{2}\frac{d[B]}{dt}=2.6\times {10^{-2}} $
$ =-\frac{1}{2}\frac{d[B]}{dt} $
$ 5.2\times {10^{-2}}=-\frac{d[B]}{dt} $
BETA
