Chemical Kinetics Question 143
Question: The rate constant of a reaction is $ 0.0693mi{n^{-1}} $ . Starting with 10 mol, the rate of the reaction after 10 minis
Options:
A) $ 0.0693molmi{n^{-1}} $
B) $ 0.0693\times 2molmi{n^{-1}} $
C) $ 0.0693\times 5molmi{n^{-1}} $
D) $ 0.0693\times {{( 5 )}^{2}}molmi{n^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ {t_{1/2}}=\frac{0.693}{k}=\frac{0.693}{0.0693}=10\min $ Reactant after 10 min = 5 mol $ Rate( \frac{dx}{dt} )=k[A]=0.0693\times 5,mol,mi{n^{-1}} $
BETA
