A) $ \frac{-E_{a}}{R} $
B) $ \ell nA $
C) $ \ell n,K $
D) $ log_{10}A $
Correct Answer: B
[b] According to Arrhenius equation, $ k=A.{e^{-E_{a}}}^{/RT} $ where k = rate constant or $ \ell nk=\ell nA-\frac{E_{a}}{RT} $ A = frequency factor $ E_{a}= $ Energy of activation.
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