Chemical Kinetics Question 152
Question: If we plot a graph between log K and $ \frac{1}{T} $ by Arrhenius equation, the slope is [UPSEAT 2001]
Options:
A) $ -\frac{E_{a}}{R} $
B) $ +\frac{E_{a}}{R} $
C) $ -\frac{E_{a}}{2.303,R} $
D) $ +\frac{E_{a}}{2.303,R} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \ln K=\ln $
$ -\frac{E_{a}}{RT} $ is Arrhenius equation. Thus plots of ln K vs 1/T will give slope $ =-E_{a}/RT $ or $ -E_{a}/2.303R $ .
BETA
