Chemical Kinetics Question 169
Question: The rate of a reaction increases four-fold when the concentration of reactant is increased 16 times. If the rate of reaction is $ 4\times {10^{-6}}mol{L^{-1}}{s^{-1}} $ when the concentration of the reactant is $ 4\times {10^{-4}}mol{L^{-1}} $ . The rate constant of the reaction will be
Options:
A) $ 2\times {10^{-4}}mo{l^{1/2}}{L^{-1/2}}{s^{-1}} $
B) $ 1\times {10^{-2}}{s^{-1}} $
C) $ 2\times {10^{-4}}mo{l^{-1/2}}{L^{1/2}}{s^{-1}} $
D) $ 25mo{l^{-1}}Lmi{n^{-1}} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ Rate\propto \sqrt{Concentration}=k\sqrt{Concentration} $
$ k=\frac{Rate}{{{(Concentration)}^{1/2}}} $
$ =\frac{4\times {10^{-6}}}{{{(4\times {10^{-4}})}^{1/2}}}=\frac{4\times {10^{-6}}}{2\times {10^{-2}}} $
$ =2\times {10^{-4}}mo{l^{1/2}}{L^{-1/2}}{s^{-1}} $
BETA
