Chemical Kinetics Question 202
Question: The reaction $ X\to Y $ is an exothermic reaction. Activation energy of the reaction for X into Y is $ 150,kJ,mo{l^{-1}} $ . Enthalpy of reaction is $ 135k,J,mo{l^{-1}} $ . The activation energy for the reverse reaction, $ Y\to X $ will be:
Options:
A) $ 280,kJ,mo{l^{-1}} $
B) $ 285kJmo{l^{-1}} $
C) $ 270kJ,mo{l^{-1}} $
D) $ 15,kJ,mo{l^{-1}} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ X\xrightarrow{{}}Y;\Delta H=-135,kJ/mol, $
$ E_{a}=150kJ/mol $ For an exothermic reaction $ {E_{a(F.R)}}=\Delta H+E{’_{a(B.R.)}} $
$ 150=-135+E{’_{a(B.R.)}} $
$ E{’_{a(B.R.)}}=285kJ/mol $
BETA
