Chemical Kinetics Question 206
Question: For a certain reaction, rate $ =k\times {{[ {H^{+}} ]}^{n}} $ . If pH of reaction changes from two to one, the rate becomes 100 times of its value at pH = 2, the order of reaction is-
Options:
A) 1
B) 2
C) 0
D) 3
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ pH=2,;r_1=k\times {{({10^{-2}})}^{n}},{Q[{H^{+}}]={10^{-pH}}} $
$ pH=1;r_2=k\times {{({10^{-1}})}^{n}} $ Given $ r_2=100r_1 $
$ \Rightarrow {{( \frac{{10^{-1}}}{{10^{-2}}} )}^{n}}=100 $
$ 10^{n}=100 $
$ \therefore n=2 $
BETA
