Chemical Kinetics Question 208
Question: Activation energy of a chemical reaction can be determined by [CBSE PMT 1998; AFMC 1999; BHU 2000]
Options:
A) Changing concentration of reactants
B) Evaluating rate constant at standard temperature
C) Evaluating rate constants at two different temperatures
D) Evaluating velocities of reaction at two different temperatures
Show Answer
Answer:
Correct Answer: C
Solution:
$ \log \frac{K_2}{K_1}=\frac{E_{a}}{2.303R}[ \frac{T_2-T_1}{T_1T_2} ] $
BETA
