Chemical Kinetics Question 216
The integrated rate equation is $ \log C_t = \log C_0 - kt $ . The straight line graph is obtained by plotting [AIEEE 2002]
Options:
A) $ time\ \text{v/s}\ log{C_{t}} $
B) $ \frac{1}{time}v/s\ {C_{t}} $
C) $ time\ v/s\ {C_{t}} $
D) $ \frac{1}{time}v/s\ \frac{1}{{C_{t}}} $
Show Answer
Answer:
Correct Answer: A
Solution:
It is similar to $ y=mx+c $
BETA
