Chemical Kinetics Question 304
Question: The half life for the reaction $ N_2O_5 $ ⇌ $ 2NO_2+\frac{1}{2}O_2 $ in $ 24,hrs $ at $ 30^{o}C $ . Starting with $ 10,g $ of $ N_2O_5 $ how many grams of $ N_2O_5 $ will remain after a period of 96 hours [KCET 1992]
Options:
A) $ 1.25,g $
B) $ 0.63,g $
C) $ 1.77,g $
D) $ 0.5,g $
Show Answer
Answer:
Correct Answer: B
Solution:
$ k=\frac{0.693}{24},hr^{-1}=\frac{2.303}{96}\log \frac{10}{a-x} $ or $ \log \frac{10}{a-x}=1.2036 $ or 1 - log (a - x) = 1.2036 or $ \log (a-x)=-0.2036 $=1.7964 $ or $ (a-x)=antilog(1.7964)=0.6258,gm $
BETA
