Chemical Kinetics Question 334
Question: After how many seconds will the concentration of the reactants in a first order reaction be halved, if the decay constant is $ 1\text{.155}\times 1{0^{\text{-3}}}{{\sec }^{-1}} $ [CBSE PMT 2000]
Options:
A) 100 sec
B) 200 sec
C) 400 sec
D) 600 sec
Show Answer
Answer:
Correct Answer: D
Solution:
$ t=\frac{2.303}{k}\log \frac{a}{a-x} $
$ t=\frac{2.303}{1.155\times {10^{-3}}}\log \frac{100}{100-50}=600\sec $
BETA
