Chemical Kinetics Question 338
Question: The rate constant for a second order reaction is $ 8\times {10^{-5}}{M^{-1}}mi{n^{-1}} $ . How long will it take a 1M solution to be reduced to 0.5 M [MH CET 2001]
Options:
A) $ 8\times {10^{-5}} $ min
B) $ 8.665\times 10^{3} $ min
C) $ 4\times {10^{-5}} $ min
D) $ 1.25\times 10^{4} $ min
Show Answer
Answer:
Correct Answer: D
Solution:
$ 8\times {10^{-5}}=\frac{1}{t}[ \frac{1}{0.5}-\frac{1}{1} ] $ ; $ 8\times {10^{-5}}=\frac{1}{t}[2-1] $
$ t=\frac{1}{8\times {10^{-5}}}=0.125\times 10^{5}=1.25\times 10^{4}min. $
BETA
