Chemical Kinetics Question 345
Relation between rate constant and temperature according to the Arrhenius equation is
Options:
A) $ {\log_{e}}A={\log_{e}}K+\frac{E_{a}}{RT} $
B) $ \log ,K=-\frac{E_{a}}{RT} + A$
C) $ {\log_{e}}K={\log_{e}}A-\frac{E_{a}}{RT} $
D) $ \log A=RT,\ln ,E_{a}-\ln ,K $
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Answer:
Correct Answer: A
Solution:
Arrhenius equation is $ \log k=\log A-\frac{E_{a}}{RT} $
BETA
