Chemical Kinetics Question 83
The velocity constant of a reaction at 290 K was found to be $ 3.2\times {10^{-3}} $ s$^{-1}$. At 300 K it will be [MP PMT 2004]
Options:
A) $ 1.28\times {10^{-2}} $
B) $ 6.4\times {10^{-3}} $
C) $ 9.6\times {10^{-3}} $
D) $ 3.2\times {10^{-4}} $
Show Answer
Answer:
Correct Answer: B
Solution:
As we know that the velocity constant becomes double by increasing the temperature by 10°C so if at 290 K, velocity constant $ =3.2\times {10^{-3}} $ then at 300 K, velocity constant $ =2(K_{290}) $
$ =2\times 3.2\times {10^{-3}} $
$ =6.4\times {10^{-3}} $ .
BETA
