Chemical Thermodynamics Question 104
Question: $ H_2(g)+Cl_2(g)\to 2HCl(g),.,\Delta H=-44kcal $
$ 2Na(s)+2HCl(g)\to 2NaCl(s)+H_2(g), $
$ \Delta H=-152,kcal $ For the reaction $ Na(s)+\frac{1}{2}Cl_2(g)\to NaCl(s),,\Delta H= $ [KCET 2000]
Options:
A) - 108 kcal
B) - 196 kcal
C) - 98 kcal
D) 54 kcal
Show Answer
Answer:
Correct Answer: B
Solution:
By (i) + (ii) ; $ Na+\frac{1}{2}Cl_2\to NaCl,,\Delta H=-196,kcal $ .
BETA
