Chemical Thermodynamics Question 159
An ideal gas expands from an initial volume V into vacuum under isothermal conditions. For this process,
Options:
A) $ \Delta U\ne 0,,W=0,and,Q\ne 0 $
B) $ \Delta U\ne 0,,W\ne 0,and,Q\ne 0 $
C) $ \Delta U\ne 0,,W\ne 0,and,Q=0 $
D) $ \Delta U=0,,W=0,and,Q=0 $
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Answer:
Correct Answer: D
Solution:
- For an isothermal expansion of an ideal gas $ \Delta U=0 $ Since $ P_{ext} $ is not zero in vacuum. $ W=-P_{ext}\Delta V\neq0 $
$ \therefore Q=0 $
BETA
