Chemical Thermodynamics Question 177
Question: For which change $ \Delta H\ne AE: $
Options:
A) $ H_2(g)+I_2(g) \to 2HI(g) $
B) $ HCl+NaOH\to NaCl+H_2O $
C) $ C(s)+O_2(g) \to CO_2(g) $
D) $ N_2(g)+3H_2(g)\to 2NH_3(g) $
Show Answer
Answer:
Correct Answer: D
Solution:
- $ \Delta H=\Delta E+\Delta nRT $ For $ \Delta H\ne \Delta E,\Delta n\ne 0 $ Where $ \Delta n $ =No, of moles of gaseous products-No. of moles of gaseous reactants (1) $ \Delta n=2-2=0 $ (2) $ \Delta n=0 $ ( $ \because $ they are either in solid or liquid state) (3) $ \Delta n=1-1=0 $ ( $ \because $ C is in solid state) (4) $ \Delta n=2-4=-2 $ Therefore, (d) is correct answer.
BETA
