Chemical Thermodynamics Question 203
Question: The “thermite reaction’ involving the reaction between ferric oxide and metallic aluminium produces molten iron. Given that $ 2A1+3/2O_2\to Al_2O_3;\Delta H_1=-400,kcal/mol $
$ 2Fe+3/2O_2\to Fe_2O_3;\Delta H_2=-200,kcal/mol. $ What is $ \Delta H $ for the formation of 1 mole of iron-
Options:
A) $ -100kcal $
B) $ -200kcal $
C) $ +100kcal $
D) $ +200kcal $
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Answer:
Correct Answer: A
Solution:
- I-II. gives, $ 2Al+Fe_2O_3\to 2Fe+Al_2O_3 $ we have $ -400-( -200 )=-200 $ ; For one mole of iron the value is $ -100 $ cal
BETA
