Chemical Thermodynamics Question 207
Question: For the reaction taking place at certain temperature $ NH_2COONH_4(s)\leftrightharpoons 2NH_3(g)+CO_2(g), $ if equilibrium pressure is 3X bar then $ \Delta _rG{}^\circ $ would be
Options:
A) $ -RT $ \ln $ 9-3RT $ \ln X
B) RT ln(4-3RT) ln X
C) $ -3RT $ ln X
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
$ \Delta {{G}^{{}^\circ }}=-RT $ ln $ K_{p};K_{p}={{( 2x )}^{2}}(1-x)=4x^{3}(1-x) $
$ \Delta G{}^\circ =-RT \ln(4X^{3}) $
$ \Delta G{}^\circ =-RT \ln K $ In $ 4-3RT $ In X
BETA
