Chemical Thermodynamics Question 220
Question: A gas undergoes change from state A to state B. In this process, the heat absorbed and work done by the gas is 5 J and 8 J, respectively. Now gas is brought back to A by another process during which 3 J of heat is evolved. In this reverse process of B to A:
Options:
A) $ 10J $ of the work will be done by the gas.
B) $ 6J $ of the work will be done by the gas.
C) $ 10J $ of the work will be done by the surrounding on gas.
D) $ 6J $ of the work will be done by the surrounding on gas.
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Answer:
Correct Answer: D
Solution:
- $ \Delta U_{AB}=q+w=+5+(-8)=-3 $
$ q=-3,\Delta U_{BA}=+3 $
$ \Delta U_{BA}=q+w $
$ \Rightarrow 3=-3+w\Rightarrow w=+6J $ (work done on the system).
BETA
