Chemical Thermodynamics Question 242
Question: The favourable conditions for a spontaneous reaction are
Options:
A) $ T\Delta S>\Delta H,\Delta H=+ve,\Delta S=+ve $
B) $ T\Delta S>\Delta H,\Delta H=+ve,\Delta S=-ve $
C) $ T\Delta S=\Delta H,\Delta H=-ve,\Delta S=-ve $
D) $ T\Delta S=\Delta H,\Delta H=+ve,\Delta S=+ve $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \Delta G=\Delta H-T\Delta S,\Delta His+ve, $
$ \Delta S $ is $ +ve;T\Delta S>\Delta H $ for spontaneous process. It will make $ \Delta G,-ve $
BETA
