Chemical Thermodynamics Question 25
Question: Heat of neutralisation for the given reaction $ NaOH+HCl\to NaCl+H_2O $ is $ 57.1 kJ mo{{l}^{-1}} $ . What will be the heat released when $ 0.25 mole $ of $ NaOH $ is titrated against $ 0.25 mole $ of $ HCl $ [CPMT 1990]
Options:
A) $ 22.5 kJ mo{{l}^{-1}} $
B) $ 57.1 kJ mo{{l}^{-1}} $
C) $ 14.3 kJ mo{{l}^{-1}} $
D) $ 28.6 kJ mo{{l}^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ 57.1\times 0.25=14.3 $ $ kJ mo{{l}^{-1}} $ .
BETA
