Chemical Thermodynamics Question 256
One mole of solid iron was vaporized in an oven at its boiling point of 3433 K and enthalpy of vaporization of iron is $ 344.3kJmol^{-1} $ . The value of entropy vaporization (in J $ mol^{-1} $ ) of iron is
Options:
100
10
C) $ -100 $
110
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \Delta S=\frac{\Delta H}{T}=\frac{334.3\times 10^{3}}{273.15}=1223.6Jmo{{l}^{-1}} $
BETA
