Chemical Thermodynamics Question 267
Question: What is the equilibrium constant if ATP hydrolysis by water produce standard free energy of $ -50kJ/mol $ under normal body conditions-
Options:
A) $ 2.66\times 10^{8} $
B) $ 5.81\times 10^{8} $
C) $ 1.18\times 10^{7} $
D) $ 1.98\times 10^{8} $
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Answer:
Correct Answer: A
Solution:
- $ \Delta G=-RT $ ln $ K_{eq} $ : Normal body temperature $ =37{}^\circ C $
$ \Rightarrow -50\frac{KJ}{mol}=8.314\frac{J}{Kmol}\times 310,\ln K_{eq} $
$ \Rightarrow 19.39=\ln K_{eq} $
$ \Rightarrow K_{eq}=2.6\times 10^{8} $
BETA
