Chemical Thermodynamics Question 37
Question: In the reaction for the transition of carbon in the diamond form to carbon in the graphite form, $ \Delta H $ is $ -453.5,cal $ . This points out that [BHU 1981; KCET 1986, 89]
Options:
A) Graphite is chemically different from diamond
B) Graphite is as stable as diamond
C) Graphite is more stable than diamond
D) Diamond is more stable than graphite
Show Answer
Answer:
Correct Answer: C
Solution:
$ C_{D}\to C_{G},,,\Delta H=-453.5cal. $ i.e. energy of $ C_{G} $ is less and thus more stable.
BETA
