Chemical Thermodynamics Question 54
Question: In the combustion of $ 2.0,gm $ of methane $ 25,kcal $ heat is liberated, heat of combustion of methane would be [MP PMT 1994]
Options:
A) $ 100,kcal $
B) $ 200,kcal $
C) $ 300,kcal $
D) $ 400,kcal $
Show Answer
Answer:
Correct Answer: B
Solution:
$ CH_4+2O_2\to CO_2+2H_2O $ Molecular weight of $ CH_4=12+4=16 $
$ \therefore $ On the combustion of 2.0gm of methane = 25.0 kcal
$ \therefore $ On the combustion of $ 16.0gm=\frac{25\times 16}{2}=200,kcal. $
BETA
